Question

The distance between electrodes of a conductivity cell is \(0.98\,\text{cm}\) and the area of cross-section is \(1.96\,\text{cm}^2\). What is the cell constant?
 

• A. \(1\,\text{cm}^{-1}\)
• B. \(1.5\,\text{cm}^{-1}\)
• C. \(2\,\text{cm}^{-1}\)
• D. \(0.5\,\text{cm}^{-1}\)

Hint:

Cell constant depends only on the geometry of the conductivity cell and not on the nature of the electrolyte.

Answer 1

The Correct Option is D

Step 1: Write the formula for cell constant.
\[ \text{Cell constant} = \frac{l}{A} \] where \(l\) is the distance between electrodes and \(A\) is the area of cross-section.
Step 2: Substitute the given values.
\[ \text{Cell constant} = \frac{0.98}{1.96} \]
Step 3: Calculate the value.
\[ \text{Cell constant} = 0.5\,\text{cm}^{-1} \]
Step 4: Conclusion.
Hence, the cell constant of the conductivity cell is \(0.5\,\text{cm}^{-1}\).