Step 1: Understanding the Concept
Separate the variables in \(x\dfrac{dy}{dx} = 2y\): \(\dfrac{dy}{y} = \dfrac{2\,dx}{x}\).
Step 2: Integrate
\(\log y = 2\log x + \log c\), so \(y = cx^2\).
Step 3: Identify the curve
This can be written \(x^2 = \dfrac{1}{c}y\), a parabola with vertex at the origin.
Its axis is along the Y-axis (positive Y-axis for \(c > 0\)).
Final Answer:
It represents parabolas with vertex at the origin and axis along the positive Y-axis.
\[ \boxed{\text{(B) }\text{a family of parabolas with vertex at the origin and axis along the positive Y-axis}} \]