Question:

The derivative of \(f(x) = 3|2 + x|\) at the point \(x_0 = -3\) is

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\(\frac{d}{dx}|x| = \frac{x}{|x|}\) for \(x \neq 0\).
Updated On: Apr 7, 2026
  • 3
  • -3
  • 0
  • None of the above
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Derivative of \(|x|\) is \(x/|x|\) for \(x \neq 0\).
Step 2: Detailed Explanation:
\(f(x) = 3|x + 2|\)
At \(x = -3\), \(x + 2 = -1<0\), so \(|x + 2| = -(x + 2)\)
\(f(x) = -3(x + 2)\)
\(f'(x) = -3\)
Step 3: Final Answer:
Derivative is \(-3\).
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