The general equation of a parabola whose axis is along the x-axis is given by:
\[
y^2 = 4ax
\]
Where \( a \) is a constant.
Differentiating both sides of this equation with respect to \( x \), we get:
\[
2y \frac{dy}{dx} = 4a
\]
Step 2: Differentiating again to find the second-order equation.
Differentiating again:
\[
2 \frac{dy}{dx} \frac{dy}{dx} + 2y \frac{d^2y}{dx^2} = 0
\]
Simplifying:
\[
\frac{dy}{dx}^2 + y \frac{d^2y}{dx^2} = 0
\]
Step 3: Conclusion.
This is a second-order differential equation, and the highest power of the highest order derivative is 1, meaning the degree is 1. Therefore, the correct degree and order are 2 and 1, respectively.