Question:
The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is
The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is
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The potential gradient is the potential difference divided by the wire length.
Updated On: Oct 1, 2026
- \(25\,G\)
- \(24\,G\)
- \(\frac{G}{24}\)
- \(\frac{G}{25}\)
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The Correct Option is C
Solution and Explanation
Step 1: Potential gradient:
\(k = \frac{V}{L} = \frac{2}{4} = 0.5\) V/m.
Step 2: EMF:
The balancing length is 80 cm \(= 0.8\) m. So \(E = k\,l = 0.5\times0.8 = 0.4\) V.
Final Answer:
The emf of the cell is 0.4 V, option (C). \[ \boxed{0.4\text{ V}} \]
\(k = \frac{V}{L} = \frac{2}{4} = 0.5\) V/m.
Step 2: EMF:
The balancing length is 80 cm \(= 0.8\) m. So \(E = k\,l = 0.5\times0.8 = 0.4\) V.
Final Answer:
The emf of the cell is 0.4 V, option (C). \[ \boxed{0.4\text{ V}} \]
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