

The total resistance in the circuit is given as:
\[ R_{\text{eq}} = 4 \, \Omega. \]
Using Ohm’s law:
\[ i = \frac{V}{R_{\text{eq}}}. \]
Substitute the given values (\( V = 8 \, \text{V} \), \( R_{\text{eq}} = 4 \, \Omega \)):
\[ i = \frac{8}{4} = 2 \, \text{A}. \]
The current \( i_1 \) is determined using the current division rule:
\[ i_1 = i \cdot \frac{R_2}{R_1 + R_2}, \]
where \( R_1 = 6 \, \Omega \) and \( R_2 = 3 \, \Omega \). Substituting the values:
\[ i_1 = 2 \cdot \frac{3}{3 + 6} = 2 \cdot \frac{3}{9} = \frac{6}{9} = \frac{2}{3} \, \text{A}. \]
The current \( i_2 \) is given by:
\[ i_2 = \frac{i_1}{2}. \]
Substitute \( i_1 = \frac{2}{3} \):
\[ i_2 = \frac{\frac{2}{3}}{2} = \frac{2}{3} \cdot \frac{1}{2} = \frac{1}{3} \, \text{A}. \]
The calculated currents are:

Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 