Step 1: Understanding the Question:
This question deals with the physical parameters that influence the critical speed (or whirling speed) of a rotating shaft carrying a rotor.
Step 2: Key Formula or Approach:
The critical speed of a shaft corresponds to its natural frequency of lateral vibration.
For a shaft carrying a rotor of mass $m$ with eccentricity $e$ and shaft stiffness $k$, the dynamic deflection $y$ at speed $\omega$ is given by:
\[ y = \frac{e}{\left(\frac{\omega_n}{\omega}\right)^2 - 1} \]
where $\omega_n = \sqrt{\frac{k}{m}}$ is the natural frequency of transverse vibration.
Step 3: Detailed Explanation:
• The natural frequency ($\omega_n$) depends on the mass ($m$) of the system and the stiffness ($k$) of the shaft.
• Eccentricity ($e$) is the distance between the center of gravity of the rotor and the geometric axis of the shaft.
• As the rotational speed approaches the critical speed, the eccentricity plays a vital role in determining the magnitude of the centrifugal force and the amplitude of vibration.
• In practical engineering systems, all three parameters (mass, stiffness, and eccentricity) dictate the vibrational amplitude and instability onset of the rotating shaft system.
Step 4: Final Answer:
The critical speed of a rotating shaft depends on mass, stiffness, and eccentricity.