
The corresponding logic gate for the given truth table is
Step 1: Understanding the given truth table.
The truth table shows that the output is 1 when either \( A \) or \( B \) is 1, but not both. This corresponds to the behavior of an XOR (exclusive OR) gate, which outputs 1 when exactly one of the inputs is 1, and 0 when both inputs are the same.
Step 2: Identifying the logic gate.
XOR gate outputs 1 when the inputs are different, and 0 when they are the same.
OR gate outputs 1 if either of the inputs is 1.
AND gate outputs 1 only when both inputs are 1.
NAND gate is the inverse of the AND gate, outputting 1 except when both inputs are 1.
Thus, the correct answer is
(A) XOR.
The equivalent capacitance of the circuit given between A and B is 
The value of current $ I $ in the adjoining circuit will be 
Let the function $ f(x) $ be defined as follows: $$ f(x) = \begin{cases} (1 + | \sin x |)^{\frac{a}{|\sin x|}}, & -\frac{\pi}{6}<x<0 \\b, & x = 0 \\ \frac{\tan 2x}{\tan 3x}, & 0<x<\frac{\pi}{6} \end{cases} $$ Then the values of $ a $ and $ b $ are: