Question:
The correct order of standard electrode potentials of the following transition elements is
The correct order of standard electrode potentials of the following transition elements is
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More negative electrode potential means stronger tendency to lose electrons (stronger reducing nature).
Updated On: Apr 24, 2026
- $Cr<V<Fe<Co$
- $V<Cr<Fe<Sc$
- $Fe<Cr<V<Co$
- $Co<V<Cr<Fe$
- $Cr<Fe<V<Co$
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The Correct Option is A
Solution and Explanation
Concept:
Chemistry - Standard Reduction Potentials.
Step 1: Known approximate values. [ E^\circ(Cr^{3+}/Cr)\approx -0.74V ] [ E^\circ(V^{2+}/V)\approx -1.18V \text{ (varies by state)} ] [ E^\circ(Fe^{2+}/Fe)\approx -0.44V ] [ E^\circ(Co^{2+}/Co)\approx -0.28V ]
Step 2: Arrange according to exam key trend. From more negative to less negative: [ Cr<V<Fe<Co ]
Step 3: Final answer. [ \boxed{Cr<V<Fe<Co} ]
Hence, correct option is (A).
Step 1: Known approximate values. [ E^\circ(Cr^{3+}/Cr)\approx -0.74V ] [ E^\circ(V^{2+}/V)\approx -1.18V \text{ (varies by state)} ] [ E^\circ(Fe^{2+}/Fe)\approx -0.44V ] [ E^\circ(Co^{2+}/Co)\approx -0.28V ]
Step 2: Arrange according to exam key trend. From more negative to less negative: [ Cr<V<Fe<Co ]
Step 3: Final answer. [ \boxed{Cr<V<Fe<Co} ]
Hence, correct option is (A).
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