Question:
The correct order of boiling points of the compounds given below is
[A)] Methoxy ethane
[B)] Propan-1-ol
[C)] Propanal
[D)] Propanone
The correct order of boiling points of the compounds given below is
[A)] Methoxy ethane
[B)] Propan-1-ol
[C)] Propanal
[D)] Propanone
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Hydrogen bonding significantly increases boiling points. Alcohols boil higher than ketones, which boil higher than aldehydes and ethers.
Updated On: Jun 4, 2025
- C > B > A > D
- B > D > C > A
- B > C > D > A
- C > A > B > D
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The Correct Option is B
Solution and Explanation
Step 1: Evaluate intermolecular forces.
Propan-1-ol (B) exhibits hydrogen bonding — strongest intermolecular force.
Propanone (D) has dipole-dipole interactions due to the carbonyl group.
Propanal (C) also has dipole-dipole interactions, slightly weaker than ketones.
Methoxy ethane (A) is an ether with only weak dipole interactions — lowest boiling point.
Step 2: Compare boiling points based on the strength of interactions: \[ \text{Propan-1-ol} > \text{Propanone} > \text{Propanal} > \text{Methoxy ethane} \] Thus, the correct order is: B > D > C > A
Propanone (D) has dipole-dipole interactions due to the carbonyl group.
Propanal (C) also has dipole-dipole interactions, slightly weaker than ketones.
Methoxy ethane (A) is an ether with only weak dipole interactions — lowest boiling point.
Step 2: Compare boiling points based on the strength of interactions: \[ \text{Propan-1-ol} > \text{Propanone} > \text{Propanal} > \text{Methoxy ethane} \] Thus, the correct order is: B > D > C > A
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