Question:

The correct increasing order of the acid strength of acids, butyric acid (I), 2-chlorobutyric acid (II), 3-chlorobutyric acid (III) and 2,2-dichlorobutyric acid (IV) is

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Acidity rules: - More electron-withdrawing groups → stronger acid - Closer to COOH → stronger effect - Multiple halogens increase acidity significantly
Updated On: May 1, 2026
  • \( I < II < III < IV \)
  • \( III < II < IV < I \)
  • \( I < III < II < IV \)
  • \( III < I < II < IV \)
  • \( IV < III < II < I \)
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The Correct Option is C

Solution and Explanation


Concept: Acidity of carboxylic acids depends on:
• Stability of conjugate base
• Electron-withdrawing groups (–I effect)
• Distance of substituent from –COOH group Inductive effect:
• Chlorine is strongly electron-withdrawing (–I effect)
• Closer Cl → stronger acidity
• More Cl atoms → stronger acidity Step-by-step analysis:
• (I) Butyric acid: No electron-withdrawing group → weakest
• (III) 3-chlorobutyric acid: Cl far from COOH → weak –I effect
• (II) 2-chlorobutyric acid: Cl near COOH → stronger –I effect
• (IV) 2,2-dichlorobutyric acid: two Cl atoms → strongest –I effect Hence order: \[ I < III < II < IV \]
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