Question:
The correct increasing order of number of electrons around the central atom in the following molecules is
The correct increasing order of number of electrons around the central atom in the following molecules is
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Count total electrons around central atom = 2 × (bond pairs + lone pairs).
Updated On: Apr 24, 2026
- $SF_6<SCl_2<PF_5$
- $SCl_2<PF_5<SF_6$
- $PF_5<SCl_2<SF_6$
- $SCl_2<SF_6<PF_5$
- $PF_5<SF_6<SCl_2$
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The Correct Option is B
Solution and Explanation
Concept:
Chemistry - Valence Shell Electron Pair Repulsion (VSEPR).
Step 1: Count electrons around central atom. * $SCl_2$: Sulfur has 2 bond pairs + 2 lone pairs = 4 pairs = 8 electrons * $PF_5$: Phosphorus has 5 bond pairs = 10 electrons * $SF_6$: Sulfur has 6 bond pairs = 12 electrons
Step 2: Arrange in increasing order. [ 8<10<12 ] So, [ SCl_2<PF_5<SF_6 ]
Step 3: Final answer. [ \boxed{SCl_2<PF_5<SF_6} ]
Hence, correct option is (B).
Step 1: Count electrons around central atom. * $SCl_2$: Sulfur has 2 bond pairs + 2 lone pairs = 4 pairs = 8 electrons * $PF_5$: Phosphorus has 5 bond pairs = 10 electrons * $SF_6$: Sulfur has 6 bond pairs = 12 electrons
Step 2: Arrange in increasing order. [ 8<10<12 ] So, [ SCl_2<PF_5<SF_6 ]
Step 3: Final answer. [ \boxed{SCl_2<PF_5<SF_6} ]
Hence, correct option is (B).
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