Question

The correct bond order of B-F bond in BF3 molecule is:

• A. 1
• B. 1 1/2
• C. 2
• D. 1 1/3

Answer 1

The Correct Option is D

Bond Order of the B-F Bond in BF₃

Let's break down the key concepts to understand the bond order of the B-F bond in the BF₃ molecule.

1. Molecular Structure of BF₃

BF₃ is a molecule consisting of one boron (B) atom in the center and three fluorine (F) atoms bonded to it. The molecule has a trigonal planar structure where the bond angles between the fluorine atoms are 120°.

2. Electron Configuration of Boron and Fluorine

The electron configuration of boron (B) is 1s² 2s² 2p¹, while fluorine (F) has an electron configuration of 1s² 2s² 2p⁵.

3. Bonding in BF₃

In BF₃, boron forms three sigma bonds with the fluorine atoms. Each B-F bond is formed by the overlap of boron's sp² hybrid orbital and fluorine's p orbital. This results in three covalent bonds between boron and fluorine.

4. Incomplete Octet of Boron

Boron in BF₃ does not have a full octet in its valence shell. It only has six electrons in its valence shell, which is a known feature of boron compounds like BF₃.

5. Molecular Orbital Theory (MO Theory)

Molecular orbital theory helps us understand the bonding in BF₃. The bond order is calculated based on the number of bonding and antibonding electrons. However, in this case, since BF₃ is stable and the bonding is covalent, we use the bond order approximation.

6. Determining the Bond Order

The bond order is calculated as: \[ \text{Bond Order} = \frac{\text{Number of Bonding Electrons} - \text{Number of Antibonding Electrons}}{2} \] For BF₃, we find that the bond order for each B-F bond is 1 1/3. This reflects the covalent nature of the bonds and the incomplete octet of boron.

Conclusion

The bond order of the B-F bond in BF₃ is: \[ \boxed{1 \frac{1}{3}} \]