Question:

The correct ascending order of the wavelengths of the following electromagnetic waves is: Ultraviolet, X-rays, Infrared, Gamma rays and Visible light.

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Remember the wavelength order of electromagnetic waves: \[ \text{Gamma} < \text{X-ray} < \text{UV} < \text{Visible} < \text{Infrared} < \text{Microwave} < \text{Radio}. \] As wavelength increases, frequency and photon energy decrease.
Updated On: Jun 18, 2026
  • X-ray, Gamma ray, Ultraviolet, Infrared, Visible light
  • Gamma ray, X-ray, Ultraviolet, Visible light, Infrared
  • Gamma ray, X-ray, Infrared, Visible light, Ultraviolet
  • Gamma ray, X-ray, Ultraviolet, Infrared, Visible light
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The Correct Option is B

Solution and Explanation

Step 1: Recall the electromagnetic spectrum.
The electromagnetic spectrum arranged in increasing wavelength is \[ \text{Gamma rays} < \text{X-rays} < \text{Ultraviolet} < \text{Visible light} < \text{Infrared} < \text{Microwaves} < \text{Radio waves}. \] Gamma rays have the shortest wavelength and highest frequency, whereas radio waves have the longest wavelength and lowest frequency.

Step 2: Arrange the given radiations.

From the standard electromagnetic spectrum, \[ \text{Gamma rays} < \text{X-rays} < \text{Ultraviolet} < \text{Visible light} < \text{Infrared}. \]

Step 3: Verify with the options.

Comparing the above order with the given choices, we find that option (2) exactly matches the ascending order of wavelengths.

Step 4: Final conclusion.

Therefore, the correct ascending order is \[ \boxed{ \text{Gamma ray} < \text{X-ray} < \text{Ultraviolet} < \text{Visible light} < \text{Infrared} } \] Hence, the correct option is \[ \boxed{(2)}. \]
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