Concept:
8085 microprocessor does not contain a direct multiplication instruction.
Therefore multiplication is performed using:
\[
\text{Repeated addition}
\]
If:
\[
\text{Product}=B\times C
\]
then:
\[
B \text{ is repeatedly added } C \text{ times}
\]
Accumulator stores intermediate and final result.
Step 1: Understand the initial instruction.
Given:
\[
\texttt{MVI A,00H}
\]
This instruction initializes accumulator with:
\[
00H
\]
Thus:
\[
A=00H
\]
This is necessary because repeated additions start from zero.
Step 2: Understand the multiplication logic.
Given:
\[
B=0AFH
\]
and
\[
C=0BH
\]
To multiply:
\[
B\times C
\]
we repeatedly perform:
\[
A=A+B
\]
and reduce count register:
\[
C=C-1
\]
until:
\[
C=0
\]
Step 3: Determine first instruction inside loop.
The first operation must add register \(B\) into accumulator.
Instruction:
\[
\texttt{ADD B}
\]
This performs:
\[
A=A+B
\]
Thus first missing instruction is:
\[
\texttt{ADD B}
\]
Step 4: Determine second instruction.
After one addition, counter register \(C\) must decrease.
Instruction:
\[
\texttt{DCR C}
\]
This decreases:
\[
C=C-1
\]
Thus second missing instruction is:
\[
\texttt{DCR C}
\]
Step 5: Determine third instruction.
Loop must continue until:
\[
C=0
\]
Instruction:
\[
\texttt{JNZ LOOP}
\]
means:
\[
\text{Jump if Zero flag is not set}
\]
Thus the loop continues while:
\[
C\neq 0
\]
Hence third missing instruction is:
\[
\texttt{JNZ LOOP}
\]
Step 6: Write complete program sequence.
The sequence becomes:
\[
\texttt{ADD B}
\]
\[
\texttt{DCR C}
\]
\[
\texttt{JNZ LOOP}
\]
Step 7: Verify with one example iteration.
Initially:
\[
A=00H
\]
After first iteration:
\[
A=A+B=00H+AFH=AFH
\]
Then:
\[
C=0BH-1=0AH
\]
Loop continues until:
\[
C=00H
\]
Thus repeated addition successfully performs multiplication.
Step 8: Write the final answer.
Hence the correct option is:
\[
\boxed{(D)\ \texttt{ADD B,\ DCR C,\ JNZ LOOP}}
\]