Question

The conductivity of a saturated solution of BaSO₄ is 3.06 × 10⁻⁶ Ω⁻¹cm⁻¹ and its equivalent conductance is 1.53 Ω⁻¹cm²eq⁻¹. The Kₛp for BaSO₄ is:

• A. 4 × 10⁻¹²
• B. 2.5 × 10⁻⁹
• C. 2.5 × 10⁻¹³
• D. 4 × 10⁻⁶

Hint:

Conductivity data can be used to find solubility.

Answer 1

The Correct Option is A

Equivalent concentration: C = κ × 1000ₑq = 3.06 × 10⁻⁶ × 10001.53 = 2 × 10⁻³ eq/L For BaSO₄: Kₛp = s² = (2×10⁻⁶)² = 4×10⁻¹²