Step 1: Recall the oxidation property of KMnO$_4$.
Hot, acidic KMnO$_4$ oxidizes any alkyl side chain attached to an aromatic ring (Ar–R) to a carboxylic acid (Ar–COOH), provided there is at least one benzylic hydrogen.
Step 2: Analyze each compound.
(A) Contains a benzyl group (–CH$_2$–), hence oxidizes to benzoic acid.
(B) Contains a tertiary carbon without a benzylic hydrogen — no oxidation.
(C) Contains a biphenyl group — no benzylic position.
(D) Contains a benzylic –CH– group with hydrogen — oxidizes to benzoic acid.
Step 3: Conclusion.
The compounds (A) and (D) form benzoic acid on oxidation.