Question

The major product of the following transformation is 

Hint:

When an epoxide is formed, reduction with LiAlH\(_4\) leads to a diol by opening the epoxide ring and adding a hydroxyl group to each carbon.

Answer 1

Step 1: m-CPBA Reaction.
The m-CPBA (meta-chloroperbenzoic acid) is used in the reaction to form an epoxide from the alkene group. In this case, the alkene (\(\text{CH}_2\text{CH}_2\)) undergoes an electrophilic addition with m-CPBA, resulting in the formation of an epoxide ring.
Step 2: Reduction with LiAlH\(_4\).
The LiAlH\(_4\) (Lithium aluminum hydride) is a strong reducing agent that can reduce epoxides to alcohols. Therefore, the epoxide formed in the first step is reduced by LiAlH\(_4\) to form a diol (two hydroxyl groups attached to the original carbon atoms).
Step 3: Conclusion.
The major product of the transformation is the formation of a diol, as shown in option (D).
Final Answer: \[ \boxed{\text{The major product is the diol.}} \]