Concept:
A compound is optically active if:
- It has at least one chiral center
- It has no internal plane of symmetry (no meso form)
Analyze each option:
(A)
Central carbon has:
\[
\text{COOH, NH}_2, H, H
\]
Two identical substituents (H, H) ⇒ achiral.
Not optically active.
(B)
Central carbon attached to:
\[
\text{COOH, OH, CH}_3, H
\]
All four substituents different ⇒ chiral center present.
Optically active.
(C)
Structure resembles glyceraldehyde type:
\[
\text{CHO, OH, CH}_2\text{OH, H}
\]
Four different groups around carbon ⇒ chiral.
Optically active.
(D)
Contains two stereocenters but has an internal plane of symmetry (meso compound).
Thus optically inactive.
Conclusion:
Optically active compounds:
B and C.