Question:

The compound(s) showing optical activity is/are

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Optical activity checklist:
  • Four different groups on carbon \( \Rightarrow \) chiral
  • Check for meso symmetry
  • Multiple chiral centers \( \neq \) always optically active
Updated On: Mar 2, 2026
  • Option a
  • Option b
  • Option c
  • Option d
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The Correct Option is B

Solution and Explanation

Concept: A compound is optically active if:
  • It has at least one chiral center
  • It has no internal plane of symmetry (no meso form)
Analyze each option: (A)
Central carbon has: \[ \text{COOH, NH}_2, H, H \] Two identical substituents (H, H) ⇒ achiral. Not optically active.
(B)
Central carbon attached to: \[ \text{COOH, OH, CH}_3, H \] All four substituents different ⇒ chiral center present. Optically active.
(C)
Structure resembles glyceraldehyde type: \[ \text{CHO, OH, CH}_2\text{OH, H} \] Four different groups around carbon ⇒ chiral. Optically active.
(D)
Contains two stereocenters but has an internal plane of symmetry (meso compound). Thus optically inactive.
Conclusion:
Optically active compounds: B and C.
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