Step 1: Analyze the reaction sequence.
- Step 1 (Li, NH$_3$): This will likely reduce the alkyl halide (OMe group in the reactant) to form an alkyl anion.
- Step 2 (O$_3$): Ozone reacts with the alkyl anion to form a ketone or aldehyde.
- Step 3 (NaBH$_4$): Sodium borohydride will reduce the aldehyde or ketone to an alcohol.
- Step 4 (TsCl, pyridine): This introduces a tosyl group to the alcohol, converting it into a tosylate.
- Step 5 (LiAlH$_4$): Lithium aluminum hydride will reduce the tosylate back to an alcohol, completing the reaction.
Step 2: Conclusion.
The compound formed as an intermediate is (B). Intermediate 2 forms during the reaction sequence.