Question:

The complete oxidation of glucose yields which of the following molecules?

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Glucose oxidation:
- Glucose → 2 Pyruvate (glycolysis).
- Pyruvate → Acetyl CoA (pyruvate dehydrogenase).
- Acetyl CoA enters TCA cycle.
  • Acetyl CoA
  • Pyruvic acid
  • Glucose-1-Phosphate
  • Fructose-1-Phosphate
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
This question tests knowledge of the products of glucose oxidation.

Step 2: Detailed Explanation:

The complete oxidation of glucose yields Acetyl CoA (A) as the molecule that enters the TCA cycle.
- Glycolysis: Glucose → 2 Pyruvic acid.
- Pyruvate dehydrogenase: Pyruvic acid → Acetyl CoA + CO2.
- Acetyl CoA enters the TCA cycle for complete oxidation to CO2 and H2O.
Other options:
- Pyruvic acid (B): An intermediate of glycolysis.
- Glucose-1-Phosphate (C): Not a product of glucose oxidation.
- Fructose-1-Phosphate (D): Not a product of glucose oxidation.
Thus, the complete oxidation of glucose yields acetyl CoA.

Step 3: Final Answer:

Thus, the complete oxidation of glucose yields acetyl CoA, which corresponds to option (A).
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