Step 1: Understanding the Question:
We need to calculate the cofactors specifically for the elements located in the second column of the given $3 \times 3$ matrix.
Step 2: Key Formula or Approach:
The cofactor $C_{ij}$ of an element $a_{ij}$ in a matrix is given by:
$$C_{ij} = (-1)^{i+j} M_{ij}$$
where $M_{ij}$ is the minor of the element (the determinant of the $2 \times 2$ matrix left after removing the $i$-th row and $j$-th column).
Step 3: Detailed Explanation:
Let the given matrix be $A$. The elements of the second column are $a_{12} = -1$, $a_{22} = 2$, and $a_{32} = 3$.
6. Cofactor of $a_{12}$:
$$C_{12} = (-1)^{1+2} \begin{vmatrix} 3 & 1 \\ -1 & 4 \end{vmatrix} = -1 [(3)(4) - (1)(-1)] = -[12 + 1] = -13$$
7. Cofactor of $a_{22}$:
$$C_{22} = (-1)^{2+2} \begin{vmatrix} 1 & 2 \\ -1 & 4 \end{vmatrix} = +1 [(1)(4) - (2)(-1)] = +[4 + 2] = 6$$
8. Cofactor of $a_{32}$:
$$C_{32} = (-1)^{3+2} \begin{vmatrix} 1 & 2 \\ 3 & 1 \end{vmatrix} = -1 [(1)(1) - (2)(3)] = -[1 - 6] = -[-5] = 5$$
The cofactors are $-13, 6$, and $5$.
Step 4: Final Answer:
The cofactors are $-13, 6, 5$, matching option (A).