The carbohydrates “Ribose” present in DNA is
A. A pentose sugar
B. Present in pyranose form
C. In “D” configuration
D. A reducing sugar, when free
E. In \( \alpha \)-anomeric form
To answer the question regarding the characteristics of the carbohydrate "Ribose" present in DNA, let's examine each option:
Based on the above analysis, the correct options are A, C, and D only. The characteristic features of ribose that are consistent with the options provided are as a pentose sugar, with D-configuration, and it being a reducing sugar when in free form.
Statement A: Ribose is a pentose sugar, which means it contains five carbon atoms. This is true. Ribose is indeed a pentose sugar, so Statement A is true.
Statement B: Ribose in DNA is primarily found in its furanose form, which is a 5-membered ring structure. It is not found primarily in the pyranose form (6-membered ring). Therefore, Statement B is false.
Statement C: Ribose is found in the D-configuration. Ribose is derived from D-galactose, and thus, it exists in the D-configuration. Therefore, Statement C is true.
Statement D: Ribose is a reducing sugar when it is free (i.e., not part of a nucleotide or in its free form). Ribose has a free aldehyde group in its open-chain form, making it a reducing sugar. Therefore, Statement D is true.
Statement E: Ribose can exist in both \( \alpha \)- and \( \beta \)-anomeric forms, depending on the position of the hydroxyl group at the anomeric carbon. However, it is not always in the \( \alpha \)-form. This statement is not always true. Therefore, Statement E is false.
The correct answer is \( \boxed{(1)} \), which corresponds to Statements A, C, and D being true.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
Match List - I with List - II:
List - I:
(A) Amylase
(B) Cellulose
(C) Glycogen
(D) Amylopectin
List - II:
(I) β-C1-C4 plant
(II) α-C1-C4 animal
(III) α-C1-C4 α-C1-C6 plant
(IV) α-C1-C4 plant


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,