Question

Match List - I with List - II. \[ {List - I (Saccharides)} \quad {List - II (Glycosidic-linkages found)} \] \[ {(A) Sucrose} \quad {(I) } \alpha 1-4 \] \[ {(B) Maltose} \quad {(II) } \alpha 1-4 { and } \alpha 1-6 \] \[ {(C) Lactose} \quad {(III) } \alpha 1-\beta 2 \] \[ {(D) Amylopectin} \quad {(IV) } \beta 1-4 \] Choose the correct answer from the options given below:

• A. (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
• B. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
• C. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
• D. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Hint:

Glycosidic linkages play a critical role in determining the structure and properties of saccharides. Make sure to recall the types of linkages when identifying saccharides.

Answer 1

The Correct Option is B

To correctly match List - I with List - II, we need to identify the glycosidic linkages present in each saccharide.

List - I (Saccharides)	List - II (Glycosidic-linkages)
(A) Sucrose	α 1-β 2
(B) Maltose	α 1-4
(C) Lactose	β 1-4
(D) Amylopectin	α 1-4 and α 1-6

Explanation of glycosidic linkages:

1. Sucrose: It is a disaccharide formed by the glycosidic linkage between glucose and fructose, which is α 1-β 2.
2. Maltose: A disaccharide consisting of two glucose units linked by an α 1-4 bond.
3. Lactose: A disaccharide composed of glucose and galactose, connected by a β 1-4 linkage.
4. Amylopectin: A branched polysaccharide with α 1-4 and α 1-6 linkages.

Correct matching according to options:

• (A)-(III): Sucrose links with α 1-β 2.
• (B)-(I): Maltose has α 1-4 linkage.
• (C)-(IV): Lactose includes β 1-4 linkage.
• (D)-(II): Amylopectin contains both α 1-4 and α 1-6 linkages.

The correct answer is (A)-(III), (B)-(I), (C)-(IV), (D)-(II).

Answer 2

Step 1: Given data.
We are to match List – I (Saccharides) with List – II (Glycosidic linkages found).

List – I (Saccharides):
(A) Sucrose
(B) Maltose
(C) Lactose
(D) Amylopectin

List – II (Glycosidic linkages found):
(I) α1 – 4
(II) α1 – 4 and α1 – 6
(III) α1 – β2
(IV) β1 – 4

Step 2: Analyze each saccharide and its linkage.
(A) Sucrose: It is a disaccharide formed by glucose and fructose with linkage α1 – β2.
Hence, Sucrose → (III) α1 – β2.

(B) Maltose: It is a disaccharide formed by two α-glucose molecules joined by α1 – 4 glycosidic linkage.
Hence, Maltose → (I) α1 – 4.

(C) Lactose: It is a disaccharide formed by β-galactose and glucose with linkage β1 – 4.
Hence, Lactose → (IV) β1 – 4.

(D) Amylopectin: It is a polysaccharide having both α1 – 4 and α1 – 6 glycosidic linkages.
Hence, Amylopectin → (II) α1 – 4 and α1 – 6.

Step 3: Final matching.
(A) Sucrose → (III) α1 – β2
(B) Maltose → (I) α1 – 4
(C) Lactose → (IV) β1 – 4
(D) Amylopectin → (II) α1 – 4 and α1 – 6

Step 4: Arrange in given format.
\[ \boxed{(A)-(I), \, (B)-(II), \, (C)-(III), \, (D)-(IV)} \]

Final Answer:
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)