Question:

The
bond angle in \(\mathrm{H}_2\mathrm{O}\) is \(104.5^{\circ}\). This fact can be explained with the help of

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Lone pairs occupy more space than bond pairs, causing bond angles to decrease.
Updated On: Apr 20, 2026
  • valence shell electron pair repulsion theory (VSEPR)
  • molecular orbital theory
  • presence of hydrogen bond
  • electronegativity difference between hydrogen and oxygen atoms
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
VSEPR theory explains molecular shapes based on electron pair repulsion.

Step 2: Detailed Explanation:
O in H\(_2\)O has 2 bond pairs and 2 lone pairs. Lone pair-lone pair repulsion>lone pair-bond pair repulsion, reducing the ideal tetrahedral angle (\(109.5^\circ\)) to \(104.5^\circ\).

Step 3: Final Answer:
Valence shell electron pair repulsion theory (VSEPR).
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