Question

The Binding energy per nucleon of \( \dfrac{3}{2} Li \) and \( \dfrac{4}{2} He \) nuclei is 5.60 MeV and 7.06 MeV, respectively.

• A. \( \dfrac{1}{3} Li \)
• B. \( \dfrac{3}{4} He \)
• C. \( 5.60 MeV \)
• D. \( 7.06 MeV \)

Hint:

The binding energy per nucleon provides information about the stability of a nucleus, with higher values indicating greater stability.

Answer 1

The Correct Option is D

Step 1: The binding energy per nucleon is calculated using the binding energy and the number of nucleons in the nucleus.
Step 2: The binding energy per nucleon for \( \dfrac{4}{2} He \) is \( 7.06 \, \text{MeV} \), which is the correct answer, based on the given data.

Final Answer: \[ \boxed{7.06 \, \text{MeV}} \]