Question:

The average velocity of a particle performing S.H.M. in one complete vibration is ( \(\mathrm{A}=\) amplitude of S.H.M., \(\omega=\) angular velocity)

Show Hint

Average velocity is displacement divided by time and the displacement over a full cycle is zero.
Updated On: Nov 13, 2026
  • zero

  • \(\mathrm{A}\omega\)

  • \(\frac{\mathrm{A}\omega}{2}\)

  • \(\frac{\mathrm{A}\omega ^{2}}{2}\)

Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
Average velocity \(=\dfrac{\text{total displacement}}{\text{time}}\).

Step 2: One complete vibration
The particle returns to its starting point, so the net displacement is zero.

Step 3: Result
Hence the average velocity is zero.

Final Answer:
The average velocity over one complete vibration is zero. \[ \boxed{\text{(A) }\text{zero}} \]
Was this answer helpful?
0
0