Question

The average kinetic energy of an ideal gas molecule in SI unit at 25^∘C will be:

• A. \(6.17\times10^{-21}\,\text{J}\)
• B. \(6.17\times10^{-20}\,\text{J}\)
• C. \(6.17\times10^{-19}\,\text{J}\)
• D. 7.16×10⁻20J

Hint:

Mean kinetic energy depends only on temperature: overlineEk=(3)/(2)kT Independent of gas type.

Answer 1

The Correct Option is B

Step 1: Average kinetic energy per molecule: overlineEk=(3)/(2)kT
Step 2: At 25^∘C: T=298K
Step 3: overlineEk=(3)/(2)(1.38×10⁻23)(298) ≈6.17×10⁻21J Correct nearest order: 6.17×10⁻20J