Question:
The average acceleration of a particle performing S.H.M. over two complete oscillations is (A = amplitude, \(\omega\) = angular frequency)
The average acceleration of a particle performing S.H.M. over two complete oscillations is (A = amplitude, \(\omega\) = angular frequency)
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Average acceleration is change in velocity divided by time.
Updated On: Nov 12, 2026
- \(\frac{A\omega ^{2}}{2}\)
- zero
- \(A\omega ^{2}\)
- \(2A\omega ^{2}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Average acceleration \(=\dfrac{\Delta v}{\Delta t}\).
Step 2: Apply to complete oscillations
After two complete oscillations the particle returns to the same position with the same velocity, so \(\Delta v=0\).
Step 3: Result
Therefore average acceleration \(=0\).
Final Answer:
The average acceleration over two complete oscillations is zero. \[ \boxed{\text{(B) }\text{zero}} \]
Average acceleration \(=\dfrac{\Delta v}{\Delta t}\).
Step 2: Apply to complete oscillations
After two complete oscillations the particle returns to the same position with the same velocity, so \(\Delta v=0\).
Step 3: Result
Therefore average acceleration \(=0\).
Final Answer:
The average acceleration over two complete oscillations is zero. \[ \boxed{\text{(B) }\text{zero}} \]
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