Concept:
For modulus functions, split at the point where the expression inside modulus becomes zero.
\[
|5 - x| =
\begin{cases}
5 - x, & x \le 5
x - 5, & x>5
\end{cases}
\]
Step 1: Split the interval
\[
\text{Area} = \int_{1}^{5} (5 - x)\,dx + \int_{5}^{6} (x - 5)\,dx
\]
Step 2: First integral
\[
\int_{1}^{5} (5 - x)\,dx
= \left[5x - \frac{x^2}{2}\right]_1^5
\]
\[
= \left(25 - \frac{25}{2}\right) - \left(5 - \frac{1}{2}\right)
= \frac{25}{2} - \frac{9}{2} = 8
\]
Step 3: Second integral
\[
\int_{5}^{6} (x - 5)\,dx
= \left[\frac{(x-5)^2}{2}\right]_5^6
= \frac{1}{2}
\]
Step 4: Total area
\[
\text{Area} = 8 + \frac{1}{2} = \frac{17}{2}
\]
Final:
\[
{\frac{17}{2}}
\]