Step 1: Represent dimensions
Let the breadth of the rectangle be $x$ m.
Then, length $= x+1$ m.
Step 2: Write the area condition
\[
\text{Area} = \text{Length} \times \text{Breadth}
\]
\[
30 = x(x+1)
\]
Step 3: Simplify into quadratic form
\[
30 = x^2 + x
\]
\[
x^2 + x - 30 = 0
\]
Step 4: Conclusion
Thus, the quadratic equation is:
\[
\boxed{x^2 + x - 30 = 0}
\]
The product of $\sqrt{2}$ and $(2-\sqrt{2})$ will be:
If a tangent $PQ$ at a point $P$ of a circle of radius $5 \,\text{cm}$ meets a line through the centre $O$ at a point $Q$ so that $OQ = 12 \,\text{cm}$, then length of $PQ$ will be:
In the figure $DE \parallel BC$. If $AD = 3\,\text{cm}$, $DE = 4\,\text{cm}$ and $DB = 1.5\,\text{cm}$, then the measure of $BC$ will be:
The discriminant of the quadratic equation $3x^2 - 4\sqrt{3}\,x + 4 = 0$ will be: