If one root of the quadratic equation $x^2 + 2x - p = 0$ is $-2$, then the value of $p$ will be:
Show Hint
- 0
- 1
- 2
- 3
The Correct Option is A
Solution and Explanation
Step 1: Substitute the given root into the quadratic equation
The equation is:
\[
x^2 + 2x - p = 0
\]
Substitute $x = -2$:
\[
(-2)^2 + 2(-2) - p = 0
\]
Step 2: Simplify
\[
4 - 4 - p = 0
\]
\[
0 - p = 0 $\Rightarrow$ p = 0
\]
Step 3: Conclusion
The value of $p$ is $0$.
\[
\boxed{p = 0}
\]
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