According to Bohr’s model of the hydrogen atom, the angular momentum \( L \) of an electron in an orbit is quantized and given by:
\( L = n\hbar, \)
where \( n \) is the principal quantum number and \( \hbar \) is the reduced Planck’s constant.
For a hydrogen atom, the radius of the \( n \)-th orbit is given by:
\( r_n \propto n^2. \)
Therefore, we can express \( n \) in terms of \( r \):
\( n \propto \sqrt{r}. \)
Substituting this into the expression for angular momentum:
\( L \propto n \propto \sqrt{r}. \)
Hence, the angular momentum of an electron in a hydrogen atom is proportional to \( \sqrt{r}. \)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)