Step 1: Understanding the Concept:
We need to find the condition for total internal reflection (TIR) at the second face of the prism. The limiting case for TIR is grazing emergence, where the angle of refraction at the second face is \( 90^\circ \), or more strictly, the angle of incidence at the second face \( r_2 \) must be greater than or equal to the critical angle \( C \).
Step 2: Key Formula or Approach:
1. Critical angle: \( \sin C = \frac{1}{\mu} \)
2. Prism relation: \( A = r_1 + r_2 \)
3. Snell's Law at first face: \( \sin i = \mu \sin r_1 \)
Step 3: Detailed Explanation:
Given \( \mu = \sqrt{2} \) and \( A = 90^\circ \).
Calculate Critical Angle \( C \):
\[ \sin C = \frac{1}{\sqrt{2}} \implies C = 45^\circ \]
For TIR at the second face, \( r_2 \ge C \). The limiting condition is \( r_2 = 45^\circ \).
Using \( A = r_1 + r_2 \):
\[ 90^\circ = r_1 + 45^\circ \implies r_1 = 45^\circ \]
Now apply Snell's law at the first face:
\[ 1 \cdot \sin i = \mu \sin r_1 \]
\[ \sin i = \sqrt{2} \sin 45^\circ \]
\[ \sin i = \sqrt{2} \times \frac{1}{\sqrt{2}} = 1 \]
\[ i = 90^\circ \]
Thus, at an incidence angle of \( 90^\circ \) (grazing incidence), the light ray strikes the second face at the critical angle. For \( i \textless 90^\circ \), \( r_1 \) would be less than \( 45^\circ \), making \( r_2 \textgreater 45^\circ \), which ensures TIR. Since \( 90^\circ \) is the boundary condition often asked in such problems, and is the only option that fits the limit calculation precisely.
Step 4: Final Answer:
The angle of incidence is \( 90^\circ \).