Step 1: Equate components:
Line 1: \((1 + 2\lambda,\ m + 3\lambda,\ 3 + 4\lambda)\). Line 2: \((4 + 5\mu,\ 1 + m\mu,\ \mu)\).
Step 2: Solve for lambda and mu:
From the z components: \(\mu = 3 + 4\lambda\). From the x components: \(1 + 2\lambda = 4 + 5(3 + 4\lambda) = 19 + 20\lambda\), so \(\lambda = -1\) and \(\mu = -1\).
Step 3: Use the y components:
\(m + 3\lambda = 1 + m\mu \Rightarrow m - 3 = 1 - m \Rightarrow 2m = 4 \Rightarrow m = 2\).
Final Answer:
\(m = 2\), option (C).
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