Question:
The angle between any two diagonals of a cube is
The angle between any two diagonals of a cube is
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Use dot product to find angle between lines in 3D.
Updated On: Mar 24, 2026
- \(45^\circ\)
- \(60^\circ\)
- \(30^\circ\)
- \(\tan^{-1}(2\sqrt{2})\)
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The Correct Option is B
Solution and Explanation
Step 1: Direction vectors of diagonals are \((1,1,1)\) and \((1,-1,1)\).
Step 2: \[ \cos\theta=\frac{1}{\sqrt{3}\sqrt{3}}=\frac{1}{3} \Rightarrow \theta=60^\circ \]
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