Question:
The \(3d\) metal that forms fluoride in +6 oxidation state is
The \(3d\) metal that forms fluoride in +6 oxidation state is
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Fluorine stabilizes high oxidation states due to its high electronegativity.
Updated On: Apr 24, 2026
- Titanium
- Chromium
- Vanadium
- Manganese
- Cobalt
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The Correct Option is B
Solution and Explanation
Concept:
Transition metals can exhibit multiple oxidation states.
High oxidation states are stabilized by highly electronegative elements like fluorine.
Step 1: Check oxidation states.
• Titanium $\rightarrow$ up to +4
• Chromium $\rightarrow$ up to +6
• Vanadium $\rightarrow$ up to +5
• Manganese $\rightarrow$ up to +7
• Cobalt $\rightarrow$ up to +3
Step 2: Identify fluoride formation.
Chromium forms \(CrF_6\) in +6 state.
Step 1: Check oxidation states.
• Titanium $\rightarrow$ up to +4
• Chromium $\rightarrow$ up to +6
• Vanadium $\rightarrow$ up to +5
• Manganese $\rightarrow$ up to +7
• Cobalt $\rightarrow$ up to +3
Step 2: Identify fluoride formation.
Chromium forms \(CrF_6\) in +6 state.
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