Question:
\[
\text { Identify substrate ' } S \text { ' in the following reaction. }
\]
\[ \mathrm{S} \xrightarrow{\text { Dimethylcadmium }} \text { Propanone }+ \text { Cadmium chloride } \]
\[
\text { Identify substrate ' } S \text { ' in the following reaction. }
\]
\[ \mathrm{S} \xrightarrow{\text { Dimethylcadmium }} \text { Propanone }+ \text { Cadmium chloride } \]
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Dialkylcadmium reagents convert acyl chlorides into ketones.
Updated On: Nov 13, 2026
- Ethyl chloride
- Ethylene dichloride
- Ethanoyl chloride
- Ethylidene dichloride
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Dialkylcadmium reacts with an acid chloride to form a ketone and cadmium chloride.
Step 2: Work Out the Acid Chloride
Propanone is \(\text{CH}_3\text{COCH}_3\). One \(\text{CH}_3\) comes from \((\text{CH}_3)_2\text{Cd}\), so the acid chloride must supply \(\text{CH}_3\text{CO}-\).
Step 3: Reaction
\(2\,\text{CH}_3\text{COCl} + (\text{CH}_3)_2\text{Cd} \rightarrow 2\,\text{CH}_3\text{COCH}_3 + \text{CdCl}_2\)
The substrate is ethanoyl chloride.
Final Answer:
The substrate is ethanoyl chloride. \[ \boxed{\text{(C) }\text{Ethanoyl chloride}} \]
Dialkylcadmium reacts with an acid chloride to form a ketone and cadmium chloride.
Step 2: Work Out the Acid Chloride
Propanone is \(\text{CH}_3\text{COCH}_3\). One \(\text{CH}_3\) comes from \((\text{CH}_3)_2\text{Cd}\), so the acid chloride must supply \(\text{CH}_3\text{CO}-\).
Step 3: Reaction
\(2\,\text{CH}_3\text{COCl} + (\text{CH}_3)_2\text{Cd} \rightarrow 2\,\text{CH}_3\text{COCH}_3 + \text{CdCl}_2\)
The substrate is ethanoyl chloride.
Final Answer:
The substrate is ethanoyl chloride. \[ \boxed{\text{(C) }\text{Ethanoyl chloride}} \]
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