Question:
\(\text{CH}_{3}\text{-CH=CH-CH}_{2}\text{-COOH}\)
What is the IUPAC name of the above compound ?
\(\text{CH}_{3}\text{-CH=CH-CH}_{2}\text{-COOH}\)
What is the IUPAC name of the above compound ?
What is the IUPAC name of the above compound ?
Show Hint
Number the chain from the carboxylic acid carbon and locate the double bond.
Updated On: Nov 12, 2026
- Pent-2-enoic acid
- Pent-3-enoic acid
- Pent-2-en-1-oic acid
- 3-Pentenol
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
The -COOH group is the principal group, so its carbon gets position 1. The name is built as parent chain + position of double bond + 'oic acid'.
Step 2: Number the chain
\(\text{C}_1\) is COOH, \(\text{C}_2\) is \(\text{CH}_2\), \(\text{C}_3=\text{C}_4\) is the double bond, and \(\text{C}_5\) is \(\text{CH}_3\).
Step 3: Name
There are five carbons (pent) and the double bond starts at \(\text{C}_3\), so the name is pent-3-enoic acid.
Final Answer:
The compound is pent-3-enoic acid. \[ \boxed{\text{(B) }\text{Pent-3-enoic acid}} \]
The -COOH group is the principal group, so its carbon gets position 1. The name is built as parent chain + position of double bond + 'oic acid'.
Step 2: Number the chain
\(\text{C}_1\) is COOH, \(\text{C}_2\) is \(\text{CH}_2\), \(\text{C}_3=\text{C}_4\) is the double bond, and \(\text{C}_5\) is \(\text{CH}_3\).
Step 3: Name
There are five carbons (pent) and the double bond starts at \(\text{C}_3\), so the name is pent-3-enoic acid.
Final Answer:
The compound is pent-3-enoic acid. \[ \boxed{\text{(B) }\text{Pent-3-enoic acid}} \]
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