\( \text{CH}_3\text{CH}_2\text{CH}_2\text{COCH}_3 \) reacts with \( \text{CH}_3 \text{MgBr} \) (one mole) followed by treatment with \( \text{H}_2 \text{O} \). The compound \( A \) formed in this reaction is
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Grignard reagents add to carbonyl compounds, forming alcohols, and are particularly useful in forming carbon-carbon bonds.
Step 1: Grignard reagent reaction.
Grignard reagents react with carbonyl compounds to form an alcohol. In this case, the reaction with the ketone forms a secondary alcohol.
Step 2: Conclusion.
The product is a secondary alcohol, \( \text{CH}_3\text{CH}_2\text{CH}_2\text{C(OH)}\text{CH}_3 \), corresponding to option (3).