The question describes what happens to tetracycline when it sits in a mildly acidic to near-neutral solution, specifically epimerization at the carbon-4 position. Let's look at what each option actually represents chemically.
Epimerization by definition means flipping one stereocentre without breaking any bond, and that is precisely the C4 inversion that mildly acidic to neutral tetracycline solutions undergo, giving the compound its name directly: epitetracycline.
So the correct answer is Epitetracycline.
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |