Question

Taking Rydberg’s constant RH=1.097×10⁷ m⁻¹, the first and second wavelength of Balmer series in hydrogen spectrum is

• A. 2000 \AA, 3000 \AA
• B. 1575 \AA, 2960 \AA
• C. 6529 \AA, 4280 \AA
• D. 6552 \AA, 4863 \AA

Hint:

Balmer series corresponds to transitions ending at n=2.

Answer 1

The Correct Option is D

For Balmer series, (1)/(λ)=RH((1)/(2²)-(1)/(n²)) For n=3,4, ₁≈6563 , ₂≈4861