Question:
Taking Rydberg’s constant RH=1.097×10⁷ m⁻¹, the first and second wavelength of Balmer series in hydrogen spectrum is
Taking Rydberg’s constant RH=1.097×10⁷ m⁻¹, the first and second wavelength of Balmer series in hydrogen spectrum is
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Balmer series corresponds to transitions ending at n=2.
Updated On: Mar 17, 2026
- 2000 \AA, 3000 \AA
- 1575 \AA, 2960 \AA
- 6529 \AA, 4280 \AA
- 6552 \AA, 4863 \AA
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The Correct Option is D
Solution and Explanation
For Balmer series,
(1)/(λ)=RH((1)/(2²)-(1)/(n²))
For n=3,4,
₁≈6563 , ₂≈4861
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