Step 1: Represent the coordinates using G.P.
Let the coordinates of the points be:
\[
A(x_1,y_1),\quad B(x_2,y_2),\quad C(x_3,y_3)
\]
Since the \(x\)-coordinates are in G.P. with common ratio \(r\),
\[
x_2=x_1r,\qquad x_3=x_1r^2
\]
Similarly, since the \(y\)-coordinates are also in G.P. with the same common ratio \(r\),
\[
y_2=y_1r,\qquad y_3=y_1r^2
\]
Thus,
\[
A=(x_1,y_1)
\]
\[
B=(x_1r,y_1r)
\]
\[
C=(x_1r^2,y_1r^2)
\]
Step 2: Find the slope of \(AB\).
\[
m_{AB}
=
\frac{y_1r-y_1}{x_1r-x_1}
\]
\[
=
\frac{y_1(r-1)}{x_1(r-1)}
\]
\[
=
\frac{y_1}{x_1}
\]
Step 3: Find the slope of \(BC\).
\[
m_{BC}
=
\frac{y_1r^2-y_1r}{x_1r^2-x_1r}
\]
\[
=
\frac{y_1r(r-1)}{x_1r(r-1)}
\]
\[
=
\frac{y_1}{x_1}
\]
Step 4: Compare the slopes.
Since
\[
m_{AB}=m_{BC},
\]
the points \(A\), \(B\), and \(C\) are collinear.
Hence, they lie on the same straight line.
Step 5: Final conclusion.
Therefore,
\[
\boxed{\text{The points }A,B,C\text{ lie on a straight line}}
\]