Suppose that 0.50 mg of precipitate is lost as a result of being washed with 200 mL liquid. What would be the relative error due to solubility loss if precipitate weighs 50 mg?
Show Hint
Relative error (%) = (mass lost total mass) $\times$ 100. Ensure consistent units before calculating.
Step 1: Concept
Relative error in gravimetric analysis due to solubility losses.
Step 2: Meaning
Relative error expresses the error as a fraction of the true value, multiplied by 100 to give a percentage.
Step 3: Analysis
\[
\text{Relative Error} = \left(\frac{\text{Mass lost}}{\text{Total mass}}\right) \times 100 = \left(\frac{0.50}{50}\right) \times 100 = 1.0%
\]
Step 4: Conclusion
The relative error due to solubility loss is 1.0%.
Final Answer: (C)