Question:

Suppose that 0.50 mg of precipitate is lost as a result of being washed with 200 mL liquid. What would be the relative error due to solubility loss if precipitate weighs 50 mg?

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Relative error (%) = (mass lost total mass) $\times$ 100. Ensure consistent units before calculating.
Updated On: May 26, 2026
  • 0.01%
  • 0.1%
  • 1.0%
  • 0.25%
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The Correct Option is C

Solution and Explanation


Step 1: Concept

Relative error in gravimetric analysis due to solubility losses.

Step 2: Meaning

Relative error expresses the error as a fraction of the true value, multiplied by 100 to give a percentage.

Step 3: Analysis

\[ \text{Relative Error} = \left(\frac{\text{Mass lost}}{\text{Total mass}}\right) \times 100 = \left(\frac{0.50}{50}\right) \times 100 = 1.0% \]

Step 4: Conclusion

The relative error due to solubility loss is 1.0%. Final Answer: (C)
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