Question:

In Capillary Electrophoresis, for a representative 50 cm capillary column operated at 30,000 V, typical net mobility for a 10 min migration time is about $2\times10^{-8}\ \text{m}^2\text{s}^{-1}\text{V}^{-1}$. Calculate the number of theoretical plates for an ion having diffusion coefficient $D = 1\times10^{-9}\ \text{m}^2\text{s}^{-1}$.

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In CE: $N = \dfrac{\mu_{\text{net}} \cdot V}{2D}$. High voltage and low diffusion coefficient give more theoretical plates (better separation).
Updated On: May 26, 2026
  • 3,000
  • 30,000
  • 3,00,000
  • 1,50,000
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The Correct Option is C

Solution and Explanation


Step 1: Concept

Theoretical plate number in capillary electrophoresis (CE).

Step 2: Meaning

The number of theoretical plates $N$ in CE is given by: \[ N = \frac{\mu_{\text{net}} \cdot V}{2D} \] where $\mu_{\text{net}}$ is the net mobility, $V$ is the applied voltage, and $D$ is the diffusion coefficient.

Step 3: Analysis

Given: \mu_{net} &= 2\times10^{-8} m^2s^{-1}V^{-1}
V &= 30{,}000 V
D &= 1\times10^{-9} m^2s^{-1} \[ N = \frac{\mu_{\text{net}} \cdot V}{2D} = \frac{(2\times10^{-8})(30{,}000)}{2\times(1\times10^{-9})} = \frac{6\times10^{-4}}{2\times10^{-9}} = 3\times10^{5} = 3{,}00{,}000 \]

Step 4: Conclusion

The number of theoretical plates $N = 3{,}00{,}000$. Final Answer: (C)
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