Suitable reaction condition for preparation of Methyl phenyl ether is
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The Williamson Ether Synthesis is a key reaction for preparing ethers. Remem ber that it’s an SN2 reaction, so it works best with primary alkyl halides (or those with minimal steric hindrance). If a tertiary alkyl halide is used, an elim ination reaction is more likely to occur.
- PhO- Na+ , MeBr
- PhO- Na+ , MeOH
- Ph - Br, MeO- Na+
- Benzene, MeBr
The Correct Option is A
Solution and Explanation
The Williamson ether synthesis involves the reaction of an alkoxide ion with a primary alkyl halide to form an ether:
General Reaction:
\[ R-O^- + R'-X \rightarrow R-O-R' + X^- \]
- \( R-O^- \): Alkoxide ion
- \( R'-X \): Alkyl halide
Reagents for Methyl Phenyl Ether (Ph-O-Me):
- Phenoxide ion (\( \text{PhO}^- \)): Derived from phenol, this acts as the alkoxide.
- Methyl bromide (\( \text{MeBr} \)): A primary alkyl halide used for the methyl group.
Reaction:
\[ \text{PhO}^- \text{Na}^+ + \text{MeBr} \rightarrow \text{Ph-O-Me} + \text{NaBr} \]
Mechanism: The phenoxide ion (\( \text{PhO}^- \)) acts as a nucleophile in an SN2 reaction, attacking the methyl carbon of the methyl bromide. This displaces the bromide ion and forms the ether linkage.
Conclusion:
Methyl phenyl ether (anisole) is prepared by reacting phenoxide ion with methyl bromide in the Williamson ether synthesis.
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