Question:
Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be:
[Take specific heat of water = 1 cal g-1°C-1 and latent heat of steam = 540 cal g-1]
Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be:
[Take specific heat of water = 1 cal g-1°C-1 and latent heat of steam = 540 cal g-1]
[Take specific heat of water = 1 cal g-1°C-1 and latent heat of steam = 540 cal g-1]
Updated On: May 22, 2024
- 31.5g
- 42.5g
- 22.5g
- 24g
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The Correct Option is C
Solution and Explanation
The correct option (C): 22.5g
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