Question:

Statement I: d-Block elements utilize their only 3d electrons for bonding on the surface of catalyst.
Statement II: This leads to strengthening of bonds in the reacting molecules.

Updated On: Apr 13, 2026
  • Both Statement I and Statement II are correct.
  • Statement I is correct but Statement II is incorrect.
  • Statement I is incorrect but Statement II is correct.
  • Both Statement I and Statement II are incorrect.
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The Correct Option is D

Solution and Explanation


Step 1: Understanding Statement I.

Statement I suggests that d-block elements use their 3d electrons for bonding on the surface of the catalyst. However, this is incorrect. In catalysis, d-block elements use both their 3d and 4s electrons for bonding, not just the 3d electrons. Hence, Statement I is incorrect.
Step 2: Understanding Statement II.

Statement II suggests that the utilization of 3d electrons strengthens bonds in the reacting molecules. This is also incorrect. The interaction of the catalyst surface with the reactant molecules weakens the bonds in the reacting molecules, facilitating easier bond breaking during the reaction. Hence, Statement II is also incorrect.
Step 3: Conclusion.

Both Statement I and Statement II are incorrect. The correct answer is (D). Final Answer: Both Statement I and Statement II are incorrect.
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