Question:

Some transition metal ions given below contain spin only magnetic moment (BM). Which of the following is not correctly matched?

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Always count unpaired electrons to calculate magnetic moment.
Updated On: Apr 24, 2026
  • $Ni^{2+}$ (Z=28) 4.73
  • $Ti^{2+}$ (Z=22) 2.84
  • $Mn^{2+}$ (Z=25) 5.92
  • $Fe^{2+}$ (Z=26) 4.90
  • $Co^{2+}$ (Z=27) 3.87
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The Correct Option is A

Solution and Explanation

Concept: \[ \mu = \sqrt{n(n+2)} \text{ BM} \]

Step 1:
For $Ni^{2+}$
Electronic configuration: $3d^8$ → $n = 2$ \[ \mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \neq 4.73 \]

Step 2:
Others match correctly
Final Conclusion:
Option (A)
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