Question:

Simplify: \[ \frac{\cos x}{1+\sin x}+\tan x= \]

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Whenever expressions contain \[ 1+\sin x, \] try rationalization using \[ 1-\sin x \] to simplify the denominator.
Updated On: Jun 26, 2026
  • \(1\)
  • \(\cos x+\sin x\)
  • \(\sin^2 x\)
  • \(\sec x\)
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The Correct Option is D

Solution and Explanation

Step 1: Write \(\tan x\) in sine-cosine form.
Given, \[ \frac{\cos x}{1+\sin x}+\tan x \] Using \[ \tan x=\frac{\sin x}{\cos x}, \] we get \[ = \frac{\cos x}{1+\sin x}+\frac{\sin x}{\cos x} \]

Step 2: Rationalize the first term.
Multiply numerator and denominator of \[ \frac{\cos x}{1+\sin x} \] by \[ 1-\sin x \] Then, \[ = \frac{\cos x(1-\sin x)} {(1+\sin x)(1-\sin x)} +\frac{\sin x}{\cos x} \]

Step 3: Simplify the denominator.
Using \[ (1+\sin x)(1-\sin x)=1-\sin^2 x, \] we get \[ = \frac{\cos x(1-\sin x)} {\cos^2 x} +\frac{\sin x}{\cos x} \] \[ = \frac{1-\sin x}{\cos x} +\frac{\sin x}{\cos x} \]

Step 4: Combine the fractions.
\[ = \frac{1-\sin x+\sin x}{\cos x} \] \[ = \frac{1}{\cos x} \]

Step 5: Convert into secant form.
Since \[ \sec x=\frac{1}{\cos x}, \] therefore, \[ = \sec x \]

Step 6: Match with the options.
The simplified expression is \[ \sec x \]

Step 7: Final conclusion.
Hence, \[ \boxed{\sec x} \]
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